Math homework question:
Write and solve an inequality to find the value of x for which the perimeter of the rectangle is less than 112.
The top of the rectangle has the equation: x+4
The side has: x
The formula for perimeter of a rectangle is 2L + 2W = P. We want the perimeter to be less than 112.
So, we get the following: 2(x) + 2(x+4) < 112
2x + 2x + 8 < 112
4x + 8 < 112
4x < 104
x < 26
In the wording of the question, the side would be less than 26 and the to is less than 30.
Hope this helps.
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