Math homework question:

Write and solve an inequality to find the value of x for which the perimeter of the rectangle is less than 112.

The top of the rectangle has the equation: x+4

The side has: x

The formula for perimeter of a rectangle is 2L + 2W = P. We want the perimeter to be less than 112.

So, we get the following: 2(x) + 2(x+4) < 112

2x + 2x + 8 < 112

4x + 8 < 112

4x < 104

x < 26

In the wording of the question, the side would be less than 26 and the to is less than 30.

Hope this helps.

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