by Pythagoras therom

10^2 = 7^2 + base^2

100-49=base^2

sqrt(51)= base

Cos θ = base/hyp = sqrt(51)/10

sinθ = perp/hyp = 7/10

secθ = 1/cosθ = 10/sqrt(51)

cotθ =cosθ/sinθ = [10/sqrt(51)]/[ 7/10]= 100/(7*sqrt(51))

Please rate and comment............if u have any confusion in answer plz let me know

best of luck

Secure Information

Content will be erased after question is completed.

Enter the email address associated with your account, and we will email you a link to reset your password.

Forgot your password?

Sign Up