write the value or values of the variable that make a denominator 0

3/(x+3)-4/(x-3)=2x/(x^2-9)

To find the value for which denominator becomes 0, equate the denominator of each term to 0.

x + 3 = 0

x = -3

x - 3 = 0

x = 3

x + 3 = 0 or x - 3 = 0

x = -3 or x = 3

ANSWER: For x = 3 and x = -3 the denominator becomes 0 for the given equation.

what value would make the denominator equal to 0...that is the first part of the question and I don't understand... thx

If you put x = 3 in the equation, it becomes

Here denominator of the 4/x-3 term and 2x/x^2-9 terms became 0.

If you put x = -3 in the equation it becomes

Here denominator of the 3/x+3 term and 2x/x^2-9 term became 0.

So, the values which make the denominator 0 are x = 3 and x = -3.

If you have any doubts please do ask.

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