write the value or values of the variable that make a denominator 0

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write the value or values of the variable that make a denominator 0

3/(x+3)-4/(x-3)=2x/(x^2-9)

May 26th, 2015



To find the value for which denominator becomes 0, equate the denominator of each term to 0.

x + 3 = 0

x = -3


x - 3 = 0

x = 3



x + 3 = 0 or x - 3 = 0

x = -3 or x = 3


ANSWER:  For x = 3 and x = -3 the denominator becomes 0 for the given equation.   


May 26th, 2015

what value would make the denominator equal to 0...that is the first part of the question and I don't understand... thx

May 26th, 2015

If you put x = 3 in the equation, it becomes


Here denominator of the 4/x-3  term and 2x/x^2-9 terms became 0.


If you put x = -3 in the equation it becomes


Here denominator of the 3/x+3  term and 2x/x^2-9 term became 0.


So, the values which make the denominator 0 are x = 3 and x = -3.

May 26th, 2015

If you have any doubts please do ask.

May 26th, 2015

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