B f o g (x) = f(g(x)) not f(x)g(x) f(x)g(x)= fg(x)
A is true as (f-g)(x) = f(x)-g(x) you subtract the functions seperately
C is true as long as g(x) never equals zero
D (f+g)(x) = is just adding the two functions seperately
B is not true
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