Find the zeros and multiplicities: f(x)=(x-3)(2x-5)^2

Calculus
Tutor: None Selected Time limit: 1 Day

I don't know how to solve this

May 26th, 2015

First we find the easier zero of (x-3) which is x = 3. This only occurs once.

Our next zero is (2x-5).

2x = 5. x = 2.5

This one has a multiplicity of 2, though, because is occurs twice (^2).

May 26th, 2015

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May 26th, 2015
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May 26th, 2015
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