I must show work to get credit.
1.What is the empirical formula of a substance composed of 56.6% potassium, 8.68% carbon, and 34.7% oxygen?
2. What is the empirical formula of a substance composed 49.89% strontium 13.67% carbon and 36.44% oxygen?
1) Assume 100 grams of compound
then we have:
56.6g of Potassium
8.68g of Carbon
and 34.7g of Oxygen
using the atomic mas of each element we can find the number of moles of each element
K: 56.6g / 39.1 = 1.45 moles
C: 8.68g / 12 = 0.72 moles
O: 34.7g / 2.17 moles
NOW, divide by the lower, in this case 0.72
K: 1.45 /0.72 = 2
C: 0.72 70.72 = 1
O: 2.177 0.72 =3
The formula of teh compound is: K2CO3
2) Assume 100 grams of compound
49.89 g Strontioun
Sr: 49.89 g /87.62 = 0.57 moles
C:13.67g / 12 = 1.14 moles
O: 36.44g / 16= 2.28 moles
NOW, divide by the lower, in this case 0.57
Sr: 0.57 /0.57 = 1
C:1.14 /0.57 = 2
O: 2.28 /0.57 = 4
The empirical formula is: SrC2O4
Thank you so much for your help.
Hello, you just posted another question, I was answering when you change the type of question, I already have the answrr if you want, just select my bis in your question, I can explain very well the answer if you want. Best regards
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?