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How many grams of CuCl can be produced if 3.75 moles of Cu2O react with HCl?
2. 2 KClO3-->2KCl+3O2
If 1.50 mol of KClO3 decomposes. How many grams of O2 will be produced?
1. From the balanced equation, you make 2 moles of CuCl for every mole of Cu2O
You have 3.75 moles of CuO so you make 7.5 moles CuCl
CuCl has a molar mass of 99.0 g/mole so 7.5 mole * 99.0 g/mole = 743 g.
2. (1.50 mol KClO3)(3 mol O2 / 2 mol KClO3)(32.00 g O2) = 72.0 g O2
Thank you so much for your help.
You are welcome. All the best
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