frequency distribution and mean

label Statistics
account_circle Unassigned
schedule 1 Day
account_balance_wallet $5

The manager of a bank recorded the amount of time each customer spent waiting in line during peak business hours one Monday. The frequency distribution below summarizes the results. Find the mean waiting time. Round your answer to one decimal place.

Waiting Time (minutes)Number of Customers
0-314
4-713
8-1114
12-158
16-196
20-233
24-273
May 26th, 2015

mean=

55061.75/679=8109.2415316642120765832106038292=8109.2

May 26th, 2015

New Microsoft Office Excel Worksheet.xlsx 

mean=sum of fx /sem of f

mean=

55061.75/679=8109.2415316642120765832106038292=8109.2

May 26th, 2015

I don't understand how the wait time could be so high when the highest time was 14. Just confused on how the mean wit time can be 8109

May 26th, 2015

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May 26th, 2015
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May 26th, 2015
Jun 23rd, 2017
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