A doubly charged helium atom whose mass is 6.6 ✕ 10-27 kg is accelerated by a vo

Physics
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A doubly charged helium atom whose mass is 6.6 ✕ 10-27 kg is accelerated by a voltage of 1600 V.

(a) What will be its radius of curvature if it moves in a plane perpendicular to a uniform 0.321 T field?
(b) What is its period of revolution?
May 26th, 2015

a) q V = 1/2 mv^2
2*1.6E-19*2500= 0.5*6.6E-27*v^2
v=492366 m/s

q v B = mv^2/r
B = m v/(q r) = 6.6E-27*492366/(2*1.6E-19*4.1E-2)=0.248 T

b)
T = 2 pi r/v = 2*pi*4.1E-2/492366=5.23E-7 s

May 26th, 2015

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