A doubly charged helium atom whose mass is 6.6 ✕ 10^{-27} kg is accelerated by a voltage of 1600 V.

a) q V = 1/2 mv^2 2*1.6E-19*2500= 0.5*6.6E-27*v^2 v=492366 m/s q v B = mv^2/r B = m v/(q r) = 6.6E-27*492366/(2*1.6E-19*4.1E-2)=0.248 T b) T = 2 pi r/v = 2*pi*4.1E-2/492366=5.23E-7 s

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