A doubly charged helium atom whose mass is 6.6 ✕ 10-27 kg is accelerated by a voltage of 1600 V.
a) q V = 1/2 mv^2
q v B = mv^2/r
B = m v/(q r) = 6.6E-27*492366/(2*1.6E-19*4.1E-2)=0.248 T
T = 2 pi r/v = 2*pi*4.1E-2/492366=5.23E-7 s
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