T(X)= (X-2)^{3} + 8

= (X^{3}-6X^{2}+12X -8) +8

T(X)=X(X^{2}-6X +12)

Intercepts axes X:

X(X^{2}-6X +12)=0

X= 0 is the only real solution (0,0)

Critic point:(turning point),(2,8)

Tâ€™(x)=3X^{2}-12X+12=X^{2}-4X+4=0 or ( x-2)^{2}=0 , X=2 , T(2)=8

T increase from x=o , T(X) keeps increasing but faster than X<2

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