= (X3-6X2+12X -8)
X= 0 is the only real solution (0,0)
Critic point:(turning point),(2,8)
T’(x)=3X2-12X+12=X2-4X+4=0 or ( x-2)2=0 , X=2 ,
T increase from x=o ,
T(X) keeps increasing but faster than X<2
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