please help with this one 2

label Mathematics
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May 27th, 2015

T(X)= (X-2)3 + 8

  = (X3-6X2+12X -8) +8

T(X)=X(X2-6X +12)

Intercepts axes X:

X(X2-6X +12)=0

X= 0  is the only real solution  (0,0)

Critic point:(turning point),(2,8)

T’(x)=3X2-12X+12=X2-4X+4=0  or ( x-2)2=0 ,  X=2 , T(2)=8 

T increase  from x=o ,   T(X) keeps increasing but faster than X<2 


May 26th, 2015

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May 27th, 2015
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May 27th, 2015
Jun 27th, 2017
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