frequency distribution and mean

label Statistics
account_circle Unassigned
schedule 1 Day
account_balance_wallet $5

The manager of a bank recorded the amount of time each customer spent waiting in line during peak business hours one Monday. The frequency distribution below summarizes the results. Find the mean waiting time. Round your answer to one decimal place.

Waiting Time (minutes)Number of Customers
0-314
4-713
8-1114
12-158
16-196
20-233
24-273
May 26th, 2015

Mean= (14*1.5+13*5.5+14*9.5+13.5*8+17.5*6+21.5*3+25.5*3)/71

(21+71.5+133+108+105+64.5+76.5)/71

579.5/71=8.16 hours

May 26th, 2015

To 1 decimal place, the mean is 8.2

May 27th, 2015

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May 26th, 2015
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May 26th, 2015
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