I need an example of how to do Factoring Trinomials (a > 1) because I am very confused!

for a trinomial a>1 we use the formula; for ax^2+bx+c

x={-b +/- sqrt[b^2-4(a)(c)]}/2a

for example 2x^2-9x+10

x={-(-9) +/- sqrt[(-9)^2-4(2)(10)]}/2(2)

x={9 +/- sqrt(1)}/4

x={9 +/- 1}/4

x=8/4 or 10/4 which are the roots. x=2 or x=5/2

therefore x=2 or 2x=5

now the solution of the equation will be:

(x-2)(2x-5)

note: the values on the right hand side change the signs when crossing to the left.

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