If I have the parabola (x^2)/3-14 and I want to have equilateral triangles perpendicular to the y-axis from y=-14 to 0, how do I set up my integral to find the cross sectional area?
This question is in progress and shall complete in 1 day, then check... Thanx
Cross sectional area = -14∫0 (x²/3 -14) dx
Best of Luck
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?