If I have the parabola (x^2)/3-14 and I want to have equilateral triangles perpendicular to the y-axis from y=-14 to 0, how do I set up my integral to find the cross sectional area?

This question is in progress and shall complete in 1 day, then check... Thanx

Cross sectional area = _{-14}∫^{0 }(x²/3 -14) dx

Best of Luck

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