Help with an precalc problem (average velocity of an object)

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The position of an object in miles after t minutes is given by s(t). Find the average velocity of the object in miles per hour for the given interval of time. Remember to convert from minutes to hours.

s(t)=0.4t^2-1/20t^3 for 3 < (also equal to) t < (also equal to ) 5.

May 27th, 2015

s(t)=0.4t^2-1/20t^3 for 3 < (also equal to) t < (also equal to ) 5.

THE ABOVE S(T) GIVEN IS A DISTANCE.

by taking derivative of distance velocity can be calculated.

v(t)=d/dt(0.4t^2-1/20t^3)

v(t)=2*0.4t^2-1 - (-3*20t^-3-1)

v(t)=0.8t + 60t^-4 for 3 < (also equal to) t < (also equal to ) 5.

by putting the t values t=3,4,and 5

v(t)=0.8(3) + 60(3)^-4 = (..a...)

similarly by putting the value of 4 and 5

v(t)=0.8(4) + 60(4)^-4 = (..b...)

.......v(t)=0.8(5) + 60(5)^-4 = (..c...)

average velocity=a+b+c/3 = answer

plz do calculation......because my laptop is just going to shutdown having no charge..........

May 27th, 2015

It says in my textbook that I'm supposed to substitute values (3,4,5) for t in the function and then use the formula for average velocity. 

Vavg=f(b)-f(a)/b-a

My teacher hasn't taught us derivatives yet. Apparently it's something which I'm supposed to learn in calculus, which I will likely never take.

May 27th, 2015

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May 27th, 2015
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