This question is in progress and shall complete in 1 day. then check... Thanx in advance

margin of error = 0.03 = z(standard error) where z is the z-value at 90% confidence. z-value = 1.8808 (10% / 2 = 0.05 in each tail) standard error = sqrt (pq/N) = sqrt [(0.5)(0.5)/N] Now, plug everything back into the equation: 0.03 = z(standard error) 0.03 = (1.8808) sqrt [(0.5)(0.5)/N] , now solve for N (0.5)(0.5)/N = [0.03/ 1.8808]^2 N = 0.25/ [0.03 / 1.8808 ]^2 = 982.6135

but ALWAYS round up to the next integer to assure the margin is less than or equal to 0.03

N = 982.61Hope that helped

Secure Information

Content will be erased after question is completed.

Enter the email address associated with your account, and we will email you a link to reset your password.

Forgot your password?

Sign Up