statistics question need sample size

Mathematics
Tutor: None Selected Time limit: 1 Day

May 27th, 2015

This question is in progress and shall complete in 1 day. then check... Thanx in advance

May 27th, 2015

margin of error = 0.03 = z(standard error) where z is the z-value at 90% confidence. 
z-value = 1.8808 (10% / 2 = 0.05 in each tail) 

standard error = sqrt (pq/N) = sqrt [(0.5)(0.5)/N] 

Now, plug everything back into the equation: 

0.03 = z(standard error) 

0.03 = (1.8808) sqrt [(0.5)(0.5)/N] , now solve for N 

(0.5)(0.5)/N = [0.03/ 1.8808]^2 

N = 0.25/ [0.03 / 1.8808 ]^2 = 982.6135

 but ALWAYS round up to the next integer to assure the margin is less than or equal to 0.03


N = 982.61

Hope that helped


May 28th, 2015

margin of error = 0.03 = z(standard error) where z is the z-value at 90% confidence. 
z-value = 1.8808 (10% / 2 = 0.05 in each tail) 

standard error = sqrt (pq/N) = sqrt [(0.5)(0.5)/N] 

Now, plug everything back into the equation: 

0.03 = z(standard error) 

0.03 = (1.8808) sqrt [(0.5)(0.5)/N] , now solve for N 

(0.5)(0.5)/N = [0.03/ 1.8808]^2 

N = 0.25/ [0.03 / 1.8808 ]^2 = 982.6135

 but ALWAYS round up to the next integer to assure the margin is less than or equal to 0.03


N = 982.61

Hope that helped


May 28th, 2015

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