Help finding the criterion variable

Statistics
Tutor: None Selected Time limit: 1 Day

A nurse is interested in whether there is a relationship between daily levels of stress and likelihood of a heart attack. The stress scores (predictor variable) and risk of heart attack values (criterion variable) from a small sample of participants are depicted below.

Stress Score: 4,0,0,3

Risk of Heart Attack: 3,6,7,1


What is the standard deviation of the criterion variable?

May 27th, 2015

Right answer is:- 0.98974332

Calculation

μ = (4×3+0×6+0×7+3×1) / (4+0+0+3) = 2.14285714

σ = √( (4×(3-2.14285714)²+0×(6-2.14285714)²+0×(7-2.14285714)²+3×(1-2.14285714)²) / (4+0+0+3) ) = 0.98974332


May 27th, 2015

Did you know? You can earn $20 for every friend you invite to Studypool!
Click here to
Refer a Friend
...
May 27th, 2015
...
May 27th, 2015
Dec 4th, 2016
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer