Help finding the criterion variable

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A nurse is interested in whether there is a relationship between daily levels of stress and likelihood of a heart attack. The stress scores (predictor variable) and risk of heart attack values (criterion variable) from a small sample of participants are depicted below.

Stress Score: 4,0,0,3

Risk of Heart Attack: 3,6,7,1


What is the standard deviation of the criterion variable?

May 27th, 2015

Right answer is:- 0.98974332

Calculation

μ = (4×3+0×6+0×7+3×1) / (4+0+0+3) = 2.14285714

σ = √( (4×(3-2.14285714)²+0×(6-2.14285714)²+0×(7-2.14285714)²+3×(1-2.14285714)²) / (4+0+0+3) ) = 0.98974332


May 27th, 2015

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May 27th, 2015
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