main algebraic solution AND CHECK!!
Mathematics

Tutor: None Selected  Time limit: 1 Day 
First we need to determine when f(x) is invalid. In this case we look at the roots which are x6 and x+2 so this means f(x) domain cannot include x=6 or x=2
then we look at g(x) and its the sqrt of 4x and a sqrt must be equal or greater to 0. so 4x>=0 x<=4 i switch signs because of the negative
The reason i did not do the numerator of f(x) since nothing there will cause it to be undefined. So now that we have the domain of our f(x) and g(x) we now must simplify it and see what x=values are allowed and what arent
So now we combine our domains and since we must be less than or equal to 4 or domain is anything less than or equal to 4 that does not include x=2, x=6 would cause our sqrt to be a negative and it is not allowed. As for x=2 it would result in the f(x) being undefined and it would result in f(x)/g(x) being undefined
Interval notation
(inf,2),(2,4] this shows that x can be anything negative infinite to 2 but not including 2 and then anything between 2 and 4 including 4. Plugin in the numbers to verify if you get undefined then it is not in the domain. Hope this helps
at 2 you would get f(x) denominator equalling 0 since 4812 =0 and at 5 sqrt(45)=1 and you cannot sqrt a negative
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