The best leaper in the animal kingdom is the puma, which can jump to a height of

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Engineering

Description

The best leaper in the animal kingdom is the puma, which can jump to a height of 3.7 m when leaving the ground at an angle of 45°. With what speed must the animal leave the ground to reach that height?

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Explanation & Answer


If it jumped vertically, it would need a velocity of:

v = √(2gh)
v = √(2*9.8*3.7) = 8.5 m/s

At an angle of 45 degrees, a velocity of 8.5/(sin45) = 11.9 m/s will result in an upwards velocity of 8.5. 

= 11.9 m/s


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