The best leaper in the animal kingdom is the puma, which can jump to a height of 3.7 m when leaving the ground at an angle of 45°. With what speed must the animal leave the ground to reach that height?
If it jumped vertically, it would need a velocity of:
v = √(2gh)
v = √(2*9.8*3.7) = 8.5 m/s
At an angle of 45 degrees, a velocity of 8.5/(sin45) = 11.9 m/s will result in an upwards velocity of 8.5.
= 11.9 m/s
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