What is the width of the deck?

Mathematics
Tutor: None Selected Time limit: 1 Day

A circular swimming pool with a diameter of 26 feet has a deck of uniform width built around it. If the area of the deck is 60(pi) square feet, find its width.

May 28th, 2015

area of the pool is (pi)*r^2

=169pi

let d be the width of the deck, then the radius is 13+d

area of the deck is given by,

deck area = (total circular area) – (pool area)

A=pi(13+d)^2-169pi

A=pi(169+26d+d^2)-169pi

A=169pi+26d(pi)+d^2(pi)-169pi

A=26d(pi)+d^2(pi)

A=60 pi

(d^2+26d-60)=0

d=-28.133 or 2.133

hence d=2 feet to the nearest whole number

May 28th, 2015

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May 28th, 2015
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May 28th, 2015
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