Given series is in AP with first term as a = -7 and common difference d = 6 .
nth term of AP is given by Tn = a+(n-1)d
therefore 83 = -7 +(n-1)6
solving we get n = 16
hence given series is sum of first 16 term of an AP there fore we can write it as
question 2: 1-4+16 -64+...----
GIven series is in GP with a =1 and r = -4
sum of infinite series of a GP is given by : a/(1-r)
hence we can denote it as
Dear student: Please find the solution enclosed
here with .. In case of any doubt please feel free to ask… If you are having some other
problem please feel free to contact me for quick & quality services..
Use my promo code: Saroj N or link: studypool.com?aid=Saroj N, and get $10 Free.