Find the maximum height ball and the time it will take to reach the ground.

Algebra
Tutor: None Selected Time limit: 1 Day

Suppose you trow a ball in the air with an initial upward velocity of 20 ft and an initial height of 10 ft. The formula is h= -16t^2+20t+10 gives the ball's height h after t seconds. Find the maximum height of the ball ad the time it will take the ball to reach the ground. 

I have to answer this question by using quadratic applications. Please make the answer simple.

May 28th, 2015

the time it will take to reach the groung is at h=0

-16t^2+20t+10=0

t={-b+/- sqrt(b^2-4(a)(c))}/2a

t={-20+/- sqrt(400+640)}/-32

t={-20+/-32.25}/-32, t= (5/8)+/-(sqrt(65)/8)

t=-0.3828 or 1.633 secons

t=1.633 sec

maximum height is h'=-32t+20

-32t=-20

t=5/8 is the time taken to reach maximum height.

max. height=-16(5/8)^2+20(5/8)+10

max. height= 65/4

May 28th, 2015

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May 28th, 2015
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May 28th, 2015
Dec 3rd, 2016
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