Find the maximum height ball and the time it will take to reach the ground.

label Algebra
account_circle Unassigned
schedule 1 Day
account_balance_wallet $5

Suppose you trow a ball in the air with an initial upward velocity of 20 ft and an initial height of 10 ft. The formula is h= -16t^2+20t+10 gives the ball's height h after t seconds. Find the maximum height of the ball ad the time it will take the ball to reach the ground. 

I have to answer this question by using quadratic applications. Please make the answer simple.

May 28th, 2015

the time it will take to reach the groung is at h=0

-16t^2+20t+10=0

t={-b+/- sqrt(b^2-4(a)(c))}/2a

t={-20+/- sqrt(400+640)}/-32

t={-20+/-32.25}/-32, t= (5/8)+/-(sqrt(65)/8)

t=-0.3828 or 1.633 secons

t=1.633 sec

maximum height is h'=-32t+20

-32t=-20

t=5/8 is the time taken to reach maximum height.

max. height=-16(5/8)^2+20(5/8)+10

max. height= 65/4

May 28th, 2015

Did you know? You can earn $20 for every friend you invite to Studypool!
Click here to
Refer a Friend
...
May 28th, 2015
...
May 28th, 2015
Jun 28th, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer