how do i solve 5^(2x+1) = 3^(4x-2)

Algebra
Tutor: None Selected Time limit: 1 Day

how would i solve this one 

May 28th, 2015

we introduce logarithms on both sides

log {5^(2x+1)}=log{3^(4x-2)}

(2x+1)*log 5=(4x-2)*log 3

(2x+1)={(4x-2)*log 3}/log 5

2x+1=(4x-2)*(log3/log5)

2x+1=(4x-2)*(0.6826)

2x+1=2.73x-1.37

1+1.37=2.73x-2x

2.37=0.73x

x=3.2466

May 28th, 2015

how did you get 2.73x

May 28th, 2015

=(4x-2)*(0.6826)

=(4*0.6826)x-2*(0.6826)

=2.7304x-1.3652

rounded off to the nearest hundredth, 

=2.73x-1.37

May 28th, 2015

okay thank you so much!!!!

May 28th, 2015

welcome

May 28th, 2015

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