How to find area of shaded region of circle

label Algebra
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May 28th, 2015

area of the semicircle= 1/2Pir^2

=1/2*3.142*6^2

=56.549cm^2

area of triangle

1/2a.b sin120

=1/2*6*6sin120

=15.588cm^2

so shaded region will be

=(56.549-15.588)

=40.961cm^2

May 28th, 2015

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May 28th, 2015
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May 28th, 2015
Oct 23rd, 2017
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