Solving a system of linear equations using elimination with multiplication and a

Algebra
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May 28th, 2015

2x + 3y = -5    (1 )                                                  -6x -7y = 1    (2)  

Multiply equation (1) by 3                                      6x + 9y = -15

Now add these two equations                                       2y = -14    (the 6x and -6x go out)

Divide by 2                                                                 2y/2 = -14/2

                                                                                   y = -7

Replace y by -7 in equation (1) 2x + 3 * -7 = -5

2x + -21 = -5

add 21 to both sides

2x + 21 -21 = 21 -5

2x =  16

divide both sides by 2

2x/2 = 16/2

x =8

Solution x = 8, and y = -7

May 28th, 2015

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