An aqueous solution is 6.00 % by mass hydrochloric acid, HCl, and has a density of 1.03 g/mL.
One liter of this solution, or l000 ml would have a mass of l030 grams. If it is 6.00% by mass HCl acid, multiply l020 grams per liter solution times 0.06 to get mass of HCI
61.8 grams of pure HCl per liter of solution. Now subtract the mass of pure HCl from the mass of the solution.
l030g solution - 61.8 g HCl = 968.2 grams of water in the solution.
Now calculate moles of HCl and moles of water.
Moles HCl = 61.8/36.5 g/mole = 1.7 moles HCl
Now find moles of water. 968.2/18 g/mole = 53.8moles water
Now add moles HCl plus moles water to get total moles.
1.7+ 53.8 = 55.5 total moles.
Mole fraction HCl = 1.7/55.5 = 0.0306
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