Please explain trinomial facroring
factoring 2x^2-9x+10 ; ax^2+bx+c
b=-9 factors of ac=20 are (4*5), (-4*-5), (10*2), (-10*-2), (20*1), (-20*-1)
the factors of (ac=20) that when added gives -9 are -4 and -5
hence the equation can be written as;
2x^2-9x+10 = 2x^2-4x-5x+10
we can factor the result as;
2x^2-9x+10 = 2x(x-2)-5(x-2)
2x^2-9x+10 = (2x-5)(x-2)
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