The boiling point of water is 100.0°C at 1 atmosphere. (Kb(water) = 0.512°C/m)

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The boiling point of water is 100.0°C at 1 atmosphere. (Kb(water) = 0.512°C/m)   


How many grams of copper(II) sulfate (159.6 g/mol), must be dissolved in 260.0grams of water to raise the boiling point by 0.300°C ?

 g copper(II) sulfate.
May 28th, 2015

DATA:

Change in boiling point (∆T)= 0.300C0

KB = 0.512

Mass of water = 260.0g

Mass of CuSO4 =?

SOLUTION:

∆T = KB m

m=∆T/ KB

m=0.3/0.512

m= 0.5859m


molality(m)= moles of CuSO4/kg of solvent

0.5859= moles of CuSO4/0.260

Moles of CuSO4= 0.5859*0.260

Moles of CuSO4 = 0.1523mol


Moles of CuSO4 = mass of CuSO4/molecular mass of CuSO4

Mass of CuSO4 = moles of CuSO4*molecular mass of CuSO4

Mass of CuSO4 = 0.1523*159.6

Mass of CuSO4 = 24.314g


May 28th, 2015

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