Algebra word problem with percentages

Algebra
Tutor: None Selected Time limit: 1 Day

you invested part of $6,000 at 16% and the balance at 10%.  In the first year the amount of interest invested at 16% earned $50 more than the amount invested at 10%. How much was invested at 10%  

May 29th, 2015

((6000-x)0.1)/(0.16x)=0.5

(6000-x)10=8

60000=18x

x=$3333.333

amount invested at 10% =$2666.67

May 29th, 2015

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