Algebra word problem with percentages

Algebra
Tutor: None Selected Time limit: 1 Day

you invested part of $6,000 at 16% and the balance at 10%.  In the first year the amount of interest invested at 16% earned $50 more than the amount invested at 10%. How much was invested at 10%  

May 29th, 2015

((6000-x)0.1)/(0.16x)=0.5

(6000-x)10=8

60000=18x

x=$3333.333

amount invested at 10% =$2666.67

May 29th, 2015

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
...
May 29th, 2015
...
May 29th, 2015
Dec 4th, 2016
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer