Description
find the roots of the following equation:
x^2+2x+6=0
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Explanation & Answer
x^2+2x+6=0; ax^2+bx+c=0
x={-b+/- sqrt(b^2-4ac)}/2a
x={-2+/- sqrt(2^2-4(1)(6))}/2(1)
x={-2+/- sqrt(-20)}/2
x={-2+/-2isqrt(5)}/2
x=-1+/- isqrt(5)
the roots are complex numbers.
x=-1+isqrt(5) and x=-1-isqrt(5)
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