solve the quadratic function.........thanks..................

User Generated

gvatzn

Mathematics

Description

find the roots of the following equation:

x^2+2x+6=0

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Explanation & Answer

x^2+2x+6=0; ax^2+bx+c=0

x={-b+/- sqrt(b^2-4ac)}/2a

x={-2+/- sqrt(2^2-4(1)(6))}/2(1)

x={-2+/- sqrt(-20)}/2

x={-2+/-2isqrt(5)}/2

x=-1+/- isqrt(5)

the roots are complex numbers.

x=-1+isqrt(5) and x=-1-isqrt(5)


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