Description
7.62g of iron reacts with 8.67g of sulfur
Fe + S FeS
1. Which reactant is the limiting reactant using the above information?
2.What is the theoretical yield of the product (in grams)?
3. What is the percentage yield if only 8g of FeS is produced?
Explanation & Answer
1.Iron is the limiting reactant
mole of iron=7.62/56
=0.136 moles
moles of sulphur= 8.67/32
=0.271 moles
mole ratio is 1:1
total mass=(8.67+7.62)
=16.29
3. what is the percentage yield=8/16.29 x 100
49.1%