3000g of CaF2 is reacted with excess H2SO4
CaF2 + H2SO4 CaSO4 + 2HF
1. What is the %yield of HF if only 1200g HF is produced?
2. What is the theoretical yield of HF?
Number of moles of CaF2 = 3000/78g/mole = 38.5 moles
CaF2 : HF = 1:2, so 1/2 = 38.5/x, where x = 77 moles.
Mass of HF is 77 moles * 20g/mole = 1540g
1) %yield of HF is 1200g/1540g = 78%
2) theoretical yield of HF is 1540g.
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