How do i verify this trigonometric identity

Calculus
Tutor: None Selected Time limit: 1 Day

cscx-cos^2xcscx=sinx

May 29th, 2015

cscx-cos^2xcscx=sinx

simplify cscx-cos^2xcscx

=1/sinx-cos^2x/sinx

factorize this

1/sinx(1-cos^2x)

but from identities 1-cos^2x=sin^2x

hence 1/sinx(sin^2x)=sinx

so coscx-cos^2xcscx=sinx

May 29th, 2015

Are you studying on the go? Check out our FREE app and post questions on the fly!
Download on the
App Store
...
May 29th, 2015
...
May 29th, 2015
Dec 10th, 2016
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer