How do i verify this trigonometric identity

Calculus
Tutor: None Selected Time limit: 1 Day

cscx-cos^2xcscx=sinx

May 29th, 2015

cscx-cos^2xcscx=sinx

simplify cscx-cos^2xcscx

=1/sinx-cos^2x/sinx

factorize this

1/sinx(1-cos^2x)

but from identities 1-cos^2x=sin^2x

hence 1/sinx(sin^2x)=sinx

so coscx-cos^2xcscx=sinx

May 29th, 2015

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May 29th, 2015
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May 29th, 2015
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