Need chemistry help with a stoichiometry question

label Chemistry
account_circle Unassigned
schedule 1 Day
account_balance_wallet $5

In the manufacturing process of sulfuric acid, sulfur dioxide is reacted with oxygen to produce sulfur trioxide. Using the equation, 2SO2 (g) + O2  2SO3 (g), if 192 g of sulfur dioxide is given the opportunity to react with an excess of oxygen to produce 225 g of sulfur trioxide, what is the percent yield of this reaction?

A. 46.8%

B. 70.2%

C. 93.7%

D. 99.9%

May 29th, 2015

calculate mass of oxygen used

=225*molar mass of O2/(2*molar mass of sulphur trioxide)

since mole ratio O2:SO3=1:2

implying mass oxygen used



so total mass= 192+45=237

percent yield


answer C. 93.7%

May 29th, 2015

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
May 29th, 2015
May 29th, 2015
Jun 26th, 2017
Mark as Final Answer
Unmark as Final Answer
Final Answer

Secure Information

Content will be erased after question is completed.

Final Answer