Need chemistry help with a stoichiometry question

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In the manufacturing process of sulfuric acid, sulfur dioxide is reacted with oxygen to produce sulfur trioxide. Using the equation, 2SO2 (g) + O2  2SO3 (g), if 192 g of sulfur dioxide is given the opportunity to react with an excess of oxygen to produce 225 g of sulfur trioxide, what is the percent yield of this reaction?

A. 46.8%

B. 70.2%

C. 93.7%

D. 99.9%

May 29th, 2015

calculate mass of oxygen used

=225*molar mass of O2/(2*molar mass of sulphur trioxide)

since mole ratio O2:SO3=1:2

implying mass oxygen used

=225*32/160

=44g

so total mass= 192+45=237

percent yield

225/237=94%

answer C. 93.7%

May 29th, 2015

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May 29th, 2015
Jun 26th, 2017
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