Need chemistry help with a stoichiometry question

Chemistry
Tutor: None Selected Time limit: 1 Day

In the manufacturing process of sulfuric acid, sulfur dioxide is reacted with oxygen to produce sulfur trioxide. Using the equation, 2SO2 (g) + O2  2SO3 (g), if 192 g of sulfur dioxide is given the opportunity to react with an excess of oxygen to produce 225 g of sulfur trioxide, what is the percent yield of this reaction?

A. 46.8%

B. 70.2%

C. 93.7%

D. 99.9%

May 29th, 2015

calculate mass of oxygen used

=225*molar mass of O2/(2*molar mass of sulphur trioxide)

since mole ratio O2:SO3=1:2

implying mass oxygen used

=225*32/160

=44g

so total mass= 192+45=237

percent yield

225/237=94%

answer C. 93.7%

May 29th, 2015

Did you know? You can earn $20 for every friend you invite to Studypool!
Click here to
Refer a Friend
...
May 29th, 2015
...
May 29th, 2015
Dec 8th, 2016
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer