main algebraic solution

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May 30th, 2015

36 inch wire is cut to 2 pieces 
every piece is of 18 inch
one shape is square 18/4 is one side of square which is 4.5 inch
then area of square= (4.5)^2 = 20.25

now for the other half shape is rectangle
where length L is twice the width w so


Area of rectangle = area of square        according to our condition

Area of rectangle= W*L

Area of rectangle= W*2W


10.125= W^2

W= sqrt(10.125)

W=3.18 inch

this is the width of rectangle that will minimize the area

for nearest tenth W= 3 inches

May 30th, 2015

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