a =1 (coefficient of X^2)

b = 6 (coefficient of X)

Vertex = -b/2a = -6/2 = -3

So x co-ordinate = -3

So y = (-3)^2 + 6*-3 +10 = 1

so the vertex = (-3,1)

Please let me know if you have any questions and best me if you are satisfactory.

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