A hockey puck struck by a hockey stick is given an initial speed v0 in the posit

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A hockey puck struck by a hockey stick is given an initial speed v0 in the positive x-direction. The coefficient of kinetic friction between the ice and the puck is μk.

(a) Obtain an expression for the acceleration of the puck. (Use the following as necessary: μk and g.)
a=

(b) Use the result of part (a) to obtain an expression for the distance d the puck slides. The answer should be in terms of the variables v0, μk, and g only.
d=
May 31st, 2015

(a) The acceleration is not dependent on the initial velocity of the puck, so you'll use Newton's 2nd law to find the magnitude of the acceleration. Since the only force (ignoring resistance from the air) is the friction between puck and ice. Also, the friction force is negative because it acts against the direction of motion, the equation is:

∑F = ma = -μmg
a = -μmg / m
a = -μg 

(b) Use the time-independent kinematics equation:

v² = v₀² + 2aΔx

Substituting -μg for a and solving for Δx (remember, v, final velocity, is zero because the puck comes to rest):

v₀² = -2(-μg)Δx
Δx = v₀² / 2μg

May 31st, 2015

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May 31st, 2015
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May 31st, 2015
Jun 24th, 2017
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