A fair die is rolled 4 times. What is the probability of having no 1 and no 2 among the rolls? Round your answer to three decimal places.

A fair die is rolled 4 times. What is the probability of having no 1 and no 2 among the rolls? Thus

P(no1 and no2 in 6 rolls) = (2/3)^4 = 0.198

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