how do you convert the polar equation r=-5cos to a rectangular equation

label Calculus
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after the -5 cos the symbole is there.

Jun 1st, 2015

multiply both sides by r 

r^2 = -5r cos theta 

since r^2 = x^2 + y^2 and x = rcos theta 

(x^2 + y^2) = -5x 

complete the square: 

x^2 +5x + (5/2)^2 + y^2 = (5/2)^2 

(x + 5/2)^2 + y^2 = 25/4 

This is an equation of a circle with center at (-5/2,0) and radius r = 5/2


Jun 1st, 2015

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Jun 1st, 2015
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Jun 1st, 2015
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