trigonometry question

Calculus
Tutor: None Selected Time limit: 1 Day

how do I do it ( -tanxcosx=-sinx )

Jun 1st, 2015

Left side = -tanx cos x

= -sinx/cos x * cosx      {note tanx = sinx /cosx)

= -sinx  (cancel off cosx)

= right hand side

Jun 1st, 2015

thanks was really helpful.

Jun 1st, 2015

Your welcome. Do you have a follow up or another question - Im free just now


Jun 1st, 2015

yes I have. ( sec x - sec x sin^2x = cos x ) 

Jun 1st, 2015

LS = (secx - secx sin^2X)

= secx ( 1-sin^2x)

=1/cosx * cos^2x     (note 1- sin^2x =cos^2x)

= cosx 

Jun 1st, 2015

can you explain to me how this website works?


Jun 1st, 2015

cos^2 x - sin^2 x = 2cos^2 x -1    ??

Jun 1st, 2015

Basically you pay for your questions, although you do get some free questions - I don;t know how many. Look at the tutors for expertise in your subjects - mine are math, statistics, algebra, English. Get a tutor with a high reputation . When you have a difficult assignment you post it as a paid question, and tutors bid. But beware! Some tutors charge a lot.

Jun 1st, 2015

Your last question - since you are new

LS = cos^2x - sin^2x

=cos^2x - (1 -cos^2x)

=2cos^2x -1

Jun 1st, 2015

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