Which is a value of x, when 3x2 + 4 = 40?
I assume its 3x^2 +4 = 40
3x^2 = 40 - 4
3x^2 = 36
x^2 = 36/3 =12
x = sqrt (12) and -sqrt(12)
= 2sqrt(3) and -2sqrt(3)
Please let me know if you have any questions and best me if you are satisfactory.
what are you supposed to do after you put the square root symbol with x and the 12?
sqrt (12) = sqrt(4*3)
sqrt (4) = 2
Taking 4 outside the root, we get sqrt (12) = 2 * sqrt(3)
= 2sqrt (3)
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