# I have an assignment of Chemistry, May you help me pleas

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yourfavoritetutor
School: Rice University

Hi Dude 😎 , the attached are files for the assignment. Go through them and inform me if any corrections and edits are required. have a nice day.

1

Acid and bases
Students name
Institutional Affiliation(s)

2

1) Calculate the pH of each solution below based on the given [H+] concentrations.
a. [H+] =3.45x10−2
pH= -log10 (3.45x10 − 2)
=1.46
b. [H+] =7.42x10−6
pH= -log10 (7.42x10 − 6)
=5.13
c. [H+] =3.95x 10−9
pH= -log10 (3.95x10 − 9)
=8.4
d. [H+] =5.48x 10−7
pH= -log10 (5.48x10 − 7)
=6.26
e. [H+] =1.62x 10−3
pH= -log10 (1.62x10 − 3)
=2.79

2) Calculate the pOH of each solution below based on the given [OH−] concentrations.
a. [OH−]=6.75 x10−4
pOH= -log10 (6.75x10 − 4)

3
=3.17
b. [OH−]=7.49x10−5
pOH= -log10 (7.49x10 − 5)
=4.13
c. [OH−]=5.92 x10−8
pOH= -log10 (5.92x10 − 8)
=7.23
d. [OH−]=6.43x10−2
pOH= -log10 (6.43x10 − 2)
=1.19
e. [OH−]=5.64 x10−9
pOH= -log10 (5.64x10 − 9)
=8.25

3) Calculate the pH of each solution below based on the given [OH−] concentrations.
a. [OH−] = 2.68 x10−8
pH= -log10 (2.68 x10 − 8)
=7.57
pH + pOH = 14
pH= 14 – pOH
=14-7.57
=6.43

4
b. [OH−]=5.64x10−3
pH= -log10 (5.64x10 − 3)
=2.25
pH + pOH = 14
pH= 14 – pOH
=14-2.25
=11.75
c. [OH−]=6.83 x10−7
pH= -log10 (6.83x10 − 7)
=6.17
pH + pOH = 14
pH= 14 – pOH
=14-6.17
=7.83
d. [OH−]=9.38x10−1
pH= -log10 (9.38x10 − 1)
=0.028
pH + pOH = 14
pH= 14 – pOH
=14-0.028
=13.972
e. [OH−]=1.44 x10−6
pH= -log10 (1.44x10 − 6)

5
=5.84
pH + pOH = 14
pH= 14 – pOH
=14-5.84
=8.16

4) Label the following solutions as either acidic or basic based on the information provided.
a. pH=4.6

acid

b. pOH =3.5 acid
c. pH =8.7 base
d. pOH =7.5 base
5) Identify the conjugate base for ...

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Anonymous
Top quality work from this guy! I'll be back!

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