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Jun 2nd, 2015
time taken = distance traveled / speed
let the distance to Phoenix = d time to Phoenix = t = d / 80 d = 80t... [eqn 1] Time to return = t + 1 = d / 70 ... [eqn 2] (a) subs [eqn 1] into [eqn 2] → t + 1 = (80t) / 70 70t + 70 = 80t 10t = 70 t = 7 so the total traveling time (for return trip) = 7 + 7 + 1 = 15 h b) subs t = 7 into [eqn 1] → d = 80 * 7 = 560 so she lives 560 miles from Phoenix ______________speed____________time______________distance going_________g________________t_________________d returning_____r________________t-k_______________d
Known variables: g, r, k Unknown variables: t, d Variables Assigned as g=60, r=75, k=1 Equations possible from data: , and ; The system is linear for t and for d. The simplest thing to do is equate the two expressions for d, and first solve for t.
Let geoffrey drove g mph on the way to visit his parents. on the way back to school he drove r mph and it took him k hour less time then it did to drive to his parents house.
Jun 2nd, 2015
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