how many different 6-symbol arrangements can be made if the first 3 must be from the letters x,y,z and the last three must be from the digits 4,5,6 (no repeats)?

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xyz456------456 has 6 kinds

yxz456------456 has 6 kinds

zxy456------456 has 6 kinds

xzy456------456 has 6 kinds

yzx456------456 has 6 kinds

zyx456------456 has 6 kinds

so 6*6=36 different arrangements in total.

Or C33 * C33=(3*2*1)^2=36

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