Physics Problem finding Magnitude

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Golfer strikes ball. The successive dis-placements are 3.5 m to the north, 4.7 m northeast, and 3 m 44◦ west of south. Start-ing at the same initial point, an expert (lucky) golfer could make the hole in a single displace-ment.
What is the magnitude of this single dis-placement?
Answer in units of m.

Jun 2nd, 2015

Dear your question is under-progress, it would be available to you as soon as it completes within next few minutes.

Jun 2nd, 2015

Please tell about proper angles....

and see this;

http://www.ux1.eiu.edu/~cfadd/1350/Hmwk/Ch03/Ch3.html

Jun 2nd, 2015

That is exactly what the problem says in my book, idk what you mean about telling you proper angles

Jun 2nd, 2015

I mean

dis-placements are 3.5 m to the north, 4.7 m (angle?) northeast, and 3 m 44◦ west of south. 

Jun 2nd, 2015

4.7 m northeast, no angle measurement

Jun 2nd, 2015

ok


Jun 2nd, 2015

Let A=3.5m ,B=4.7m ,C=3m

Ax = 0

Rx = Ax + Bx + Cx

Ry = Ay + By + Cy


As B is in mid of north-east, so

Bx = B cos 45

Bx = (4.7)(0.707)

Bx = 3.3229

Cx = C cos 44o

Cx = (3)(0.9998)

Cx = 2.9995

Rx = 0 + 3.3229 + 2.9995

Rx = 6.3

Now

Ay = 3.5

By = B sin 45o

By = (4.7)(0.707)

By = 3.3229

Cy = - C sin 46o

Cy = - (3)(0.901)

Cy = - 2.705

Ry = 3.5 + 3.3229 - 2.705

Ry = 4.12

Resultant vector R;

R = SQRT [ Rx2 + Ry2 ]

R = SQRT [ (6.3)2 + (4.12)2 ]

R = 7.5m


Jun 2nd, 2015

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Jun 2nd, 2015
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Jun 2nd, 2015
Jun 29th, 2017
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