Ethanol (C2H5OH) is produced from the fermentation of sucrose in the presence of enzymes.
Determine the theoretical yield and the percent yields of ethanol if 735 g sucrose undergoes fermentation and 305.5 g ethanol is obtained.
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From your equation the theoretical yield is straight forward 342g C12H22O11(a) gives 184g C2H5OH so 735g, in theory yields 395g, but in practice it gives 305.5g so % yield = 305.5/395 x100 =77.3%
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