Determine the theoretical yield and the percent yields of ethanol if 735 g sucrose undergoes ferment

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Ethanol (C2H5OH) is produced from the fermentation of sucrose in the presence of enzymes.

Determine the theoretical yield and the percent yields of ethanol if 735 g sucrose undergoes fermentation and 305.5 g ethanol is obtained.

Jun 2nd, 2015

Please let me know if you need any clarification. I'm always happy to answer your questions.

From your equation the theoretical yield is straight forward 342g C12H22O11(a) gives 184g C2H5OH 
so 735g, in theory yields 395g, but in practice it gives 305.5g 
so % yield = 305.5/395 x100 =77.3%

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jun 2nd, 2015

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Jun 2nd, 2015
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