Science
For the reaction Fe2O3(s) + 3H2(g)2Fe(s) + 3H2O(g) H° = 98.8 kJ and S° = 143

Question Description

For the reaction


Fe2O3(s) + 3H2(g)2Fe(s) + 3H2O(g)

H° = 98.8 kJ and S° = 143 J/K

G° for this reaction would be negative at temperatures (above, below) K.

Enter above or below in the first box and enter the temperature in the second box. Assume that H° and S° are constant.

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Final Answer

Please let me know if you need any clarification. I'm always happy to answer your questions.


98800 -(T*143) <0

690.91 <T

So temperature should be above 690.91 k or above 691 k


Please let me know if you need any clarification. I'm always happy to answer your questions.

Gopal_R (1109)
University of Maryland

Anonymous
This is great! Exactly what I wanted.

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