x(5x+4)=2x^2-13x+6

Please let me know if you need any clarification. I'm always happy to answer your questions.

First remove the parenthness:

5x^2+4x=2x^2-13x+6

Then take all terms to the left:

5x^2+4x-2x^2+13x-6=0

3x^2+17x-6=0

Then find discriminant D:

D=289-4*3*(-6)=361

sqrtD=sqrt 361=19

x1 =(-17-19)/(2*6)=-3

x2 =(-17+19)/(2*6)=2/12=1/6

So, the solution is: x1=-3 and x2=1/6

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