A ball is thrown from an initial height of 3 feet with an initial upward velocity of 27ft/s. The ball's height h (in feet) after t seconds is given by the following: h=3+27t-16t^2
Please let me know if you need any clarification. I'm always happy to answer your questions.
You can solve this equation quadratically by plugging in 13 for h which leaves you with the equation:
13 = 3 + 27t - 16t^2
Solving for t gives you t = 0.5489 and t = 1.139.
Thank you so much!!
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