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Chemistry Homework Help

Question Description

How many grams of CaCl2 are needed to prepare 1.0 L of a 1.0M solution?

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Final Answer

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Molar mass CaCl2 = 111g/mol

Number of moles of CaCI2in solution is 1.0L*1.0M = 1 mole

Mass required = 111g/mol*1 mole = 111g of CaCI2.

Answer: 111g of CaCI2

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tsveiukolha (653)
UC Berkeley

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