How many grams of CaCl2 are needed to prepare 1.0 L of a 1.0M solution?
Thank you for the opportunity to help you with your question!
Molar mass CaCl2 = 111g/mol
Number of moles of CaCI2in solution is 1.0L*1.0M = 1 mole
Mass required = 111g/mol*1 mole = 111g of CaCI2.
Answer: 111g of CaCI2
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?